$\left(x^4\right)^3$
$\frac{dy}{dx}=\frac{1}{\sqrt{y}-y}$
$\int\sec\left(x\right)\left(9\sec\left(x\right)+\tan\left(x\right)\right)dx$
$2x^3\:0-9x^2\:+12x\:-2$
$\left(x^2+3\right)^4$
$-540-713$
$7\left(x-4\right)-3\left(2x-5\right)$
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