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$t^2\frac{dx}{dt}+3tx=t^4\ln\:\:\left(t+1\right)$

Final answer to the exercise

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Other solved exercises

$\left(7x^5+y^3\:\right)\left(7x^5-y^3\:\right)$

$9y^2-30y+1$

$y'-2y\:=\:xe^{2x}$

$\left(-1-x\right)^2$

$f\left(x\right)\:=\:7\left(3+4x\right)-2x\left(x+2\right)$

$\left(abc-1\right)\left(abc+1\right)$

$6,829+54,3+3,29$
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