$\frac{dy}{dx}-\frac{y}{x}=3x^2$
$6x^2+4x-2$
$\int_{-\infty}^1\left(4e^{-3x}\right)dx$
$\int7e^{8x}dx$
$6r-10\ge\:5r-19$
$\int\frac{e^{\sqrt{x}}3^{e^{\sqrt{x}}}}{\sqrt{x}}dx$
$6x-2<8+x$
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