$\left(2x^2-3x+4\right)\left(7x+2\right)$
$-16t^2+70t+4=-5$
$\lim_{h\to0}\:\frac{\left(h-2\right)}{x^2+2x+1+h+hx}\:\cdot\left(\frac{1}{h}\right)$
$13.26+2.78-17.49+6.174-6$
$\frac{d^2}{dx^2}\left(-\frac{x}{2y^3}\right)$
$-t^2+2t+15$
$\frac{4\left(x+3\right)}{9}-\frac{3\left(x-2\right)}{5}$
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