$\left(a-d\right)^5$
$x^2-3x-20$
$\left(-b-4\right)^2$
$3^8\cdot3^{-4}$
$40\cdot89$
$\frac{x-4}{4}+\frac{x-12}{6}=\frac{x}{3}$
$\frac{dy}{dx}=-2\left(2-x\right)y$
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