$x\cos\left(2\right)x$
$\frac{y^{10}}{y^8}$
$-8\le-1+3\le11$
$4y^2-12y-9$
$x-9=9$
$\int\frac{\left(2x^2+8x-3\right)}{\left(2x+1\right)\left(4x^2+1\right)}dx$
$\frac{-150}{-10}$
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