$\lim_{x\to\infty}\left(\left(\frac{n+1}{n-5}\right)^{6n-2}\right)$

$4<x^2$

$\frac{1}{5}\int\frac{1}{1-\left(u\right)^2}dx$

$\lim\:_{x\to\:\infty\:}\left(\ln\:\left(e^x+1\right)\right)-\lim_{x\to0}\left(\ln\left(e^x+1\right)\right)$

$3x^3-12x^2+9x-36$

$5\:x\:22\:-\:62\:x\:4\:+\:8\:$

$\int_0^{\pi}\left(\frac{cost}{\sqrt{1+sin^2t}}\right)dx$