$\frac{7}{10}a+\frac{3}{2}=\frac{3}{5}a+2$

$\:2a^3+2b^3-3ab^2-3a^2b$

$\left(-65\right)\cdot55$

$3x\:-\:\frac{x}{2}$

$z^3z^5m^3$

$\frac{d}{dx}\frac{\sqrt{2+x}\left(3-x\right)^4}{\left(x+1\right)^5}$

$-4\left(-1\right)^2\left(\frac{1}{2}\right)+2\left(-1\right)-3\left(\frac{1}{2}\right)+5\left(-1\right)\left(\frac{1}{2}\right)$