$\int\tan8x\:dx$
$\left(2b^2\right)^3$
$2x-4<x+3$
$1+tan\left(-2x\right)=\frac{3-\sqrt{3}}{3}$
$\sqrt{2}\cdot\sqrt{5}$
$30+2\left(-67\right)$
$\sqrt{\left(\log_{4}3x\right)}$
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