$\frac{d}{dx}\:\frac{x^3}{3}$
$9x+10-4x$
$\int\frac{1}{\sin^2\left(2x\right)\cos^4\left(2x\right)}dx$
$5x^2-18x+9$
$9r^2-4r+1$
$\left(5x^3-2y\right)^2$
$\frac{6^{24}}{2^{24}}$
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