$\int\frac{1}{\left(x^2+4x+8\right)^2}dx$
$\frac{a^2-16}{4+a}$
$\left(\sqrt{5}\right)^0$
$\:\frac{4+4\cos\:\left(2\beta\:\right)}{7\sin\:\left(2\beta\:\right)}=\frac{4}{7}\tan\left(\beta\:\right)$
$xy^2-y^2w$
$y=-5x^2+3x-4$
$\int_{-1}^{x^4}sin\left(t\right)cos\left(t\right)dt$
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