$4x^3+4x^2-7x+2$
$\left(\frac{3y^5}{y}\right)^2$
$\frac{x}{x-1}-1=\frac{1}{2}$
$5=sec^2x+3$
$\frac{4}{s^2+4s+4}$
$\frac{dy}{dx}=\frac{\left(1-x\right)}{y^{16}x}$
$\left(ax+b\right)^2$
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