$10x^2-13x-3$
$\left(2x^2-4y^5\right)^2$
$a^2-6a+-3$
$\left(-5\right)6+\left(-12\right)-6\left(9\right)$
$y^2+2y^2-3y^2$
$1\frac{1}{x}$
$\left(b^3-m^4\right)\left(b^3+m^4\right)$
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