$\lim_{x\to0}\left(\frac{x^3+x^2+6x}{x^2-2x}\right)$
$\left(2m-5\right)\left(m^2-6m\right)$
$2x+3y-4x+8y$
$\frac{dp}{dt}=ke^{-t}$
$b3\:-\:125$
$3\left(x^2-2\right)=6\left(x-1\right)$
$a^5\cdot a^2$
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