$\int\frac{1}{\sqrt{9x^2+16}}dx$
$5x+10>12x-4$
$\left(3\right)\left(m^5n^2\right)\left(-m^4n^2\right)$
$\sec^2\left(80.103\right)$
$\int\frac{\left(8x^5-2x^2-3x+5\right)}{6x}dx$
$50y^2-4x^2$
$-2.8<-7.1+x$
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