$x^2-12x=-36$
$7\left(2\right)-5>2-5\left(2\right)$
$\left(7x+1\right)\left(x^4-x^3-9x\right)$
$\left(-36\right)\:\cdot\left(-13\right)$
$\frac{\tan\left(25\right)+\tan\left(110\right)}{1-\tan\left(25\right)\tan\left(110\right)}$
$11x+3y=7$
$7t^{-3}$
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