$\int_1^2\left(x^3e^{\frac{x}{2}}\right)dx$
$2x+4<x-3$
$\frac{dy}{dx}+\frac{y}{x}=e^{-x}$
$\int_6^{\infty}\left(\frac{5}{\sqrt{x}}\right)dx$
$10b-8=6b$
$18\:\sqrt[4]{a^3}b^2$
$\left(12.1\right)\cdot\left(-30.6\right)$
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