$\int cos^5x\cdot tan^3\left(x\right)dx$

$y-3^2$

$x^2-8x+8\:>4-4x$

$\frac{1}{x}=\frac{x-1}{x+2}$

$\left(\frac{3}{8}c^2+\frac{2}{9}d^3u\right)^2$

$\frac{9x}{4}\cdot\frac{4x-4}{3x}$

$\log_{a^2}\left(2^2y^6\right)+2\log_a\left(\frac{1}{y^3\left(\sqrt{2}\right)}\right)-3\frac{\log\left(\frac{2}{4}\right)}{\log\left(a\right)}$