$-4x<8$
$-xy^2+y^2$
$\left(1+a^4\right)^2$
$\frac{\sqrt[3]{64}}{\left(2^2\right)}$
$\left(x^3+4\right)\left(x^3+8\right)$
$-4n+8+9n-2$
$\log\left(2x-8\right)+\log\left(3x-10\right)=\log\left(66\right)$
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