$\left(4+a\right)\left(x-2\right)$

$4m^2-20am$

$\frac{in\left(x^2+2x+1\right)}{2}+\frac{1}{x+1}$

$\left(tu^{-4}v^0\right)\left(t^7u^0v^0\right)\left(t^0u^{-1}v^7\right)$

$\lim_{x\to0}6\left(x+1\right)\left(x-2\right)^2$

$-\left(3-5+6\right)-3+6-\left(-2\right)\cdot6+\left(-3\right)$

$\frac{v^0}{4u^{-1}}v^{-1}$