$6^{3x-4}=36^{x+1}$
$1+2-3x^2-3x^4+3x^4+3+2$
$\int x^3\left(x^2+36\right)dx$
$\left(2xy^2z^3+3w\right)^2$
$48\left(1-1^{-0.24}\right)$
$\frac{dv}{dt}=1-2v$
$x^3+11x^2+28x$
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