$\left(\tan\left(y\right)\right)^2dy=\left(\sin\left(x\right)\right)^3dx$

$\left(\frac{1}{3}+w\right)^2$

$y=\sqrt[5]{\frac{\left(5x+1\right)\left(x+3\right)^2}{\left(x^4+6\right)\left(x+8\right)}}$

$\int\left(\csc u\left(-3\right)\right)du$

$-1^3\cdot x$

$3x\:-x\:+\:45\:-\:x\:+\:23$

$x^{\frac{1}{2}}+3x^{-\frac{1}{2}}=10x^{-\frac{3}{2}}$