$r^2-6r+9=0$
$\left(2xy^3-5y^5\right)^2$
$\lim_{x\to-1}\left(\frac{3x^4+9x^3+x+7}{x+1}\right)$
$.005+.4+.03$
$9s-8\left(7s+4\right)$
$=\frac{2\left(-7\right)^2+3\left(-7\right)-27}{\left(-7\right)-3}$
$1-0.35$
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