$xy'=-4y+xe^{\frac{x^5}{5}}$
$18-15+-\left(-22\right)+0$
$\:b^2\:-\:5b\:+\:6$
$\left(\frac{5a^6b^2c^3}{\left(b^2c^4g^{-5}\right)\left(5b^6a^3g^7\right)}\right)$
$14^2$
$\left(4u-3\right)\left(-u^2+u+3\right)$
$\int\frac{3x^2+10x+24}{x+1\left(x^2+16\right)}dx$
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