$\frac{9a^{2}b^{4}}{3a^{3}b^{-3}}$
$\frac{dy}{dx}=\frac{cos^2x-2xy}{x^2}$
$y'\:=\:8x\:-y$
$4x^2-3x+7$
$3x^2+3x\left(0\right)+\left(0\right)^2+24\left(0\right)+\left(0\right)^2+24x+12\left(0\right)$
$\left(9x^2+18b\right)^2$
$9x^2-24x=-14$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!