$\sqrt{-\frac{98}{27}}+0,06$
$\lim_{x\to1}\left(\frac{1-x^2}{1-\sqrt{x}}\right)$
$\left(\frac{\sin^2x}{\sec^2x-1}\right)=\cos^2x$
$10+6+6+5+5+5+5+5+5-2$
$-\left(-2\right)-\left(-26\right)$
$6x^2-x-15$
$x+\frac{1}{2}^2$
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