$3+5\cdot\left(-2\right)-4+12:\left(-6\right)$
$\left(1-m^3\right)^3$
$\frac{dy}{dt}y=\left(t+3\right)\left(t+8\right)\left(t+5\right)$
$\sqrt[5]{n^4}$
$96x-24x$
$x^2\ln\left(x\right)dx=\left(\frac{\left(y+1\right)}{y}\right)dy$
$4-2x\le3x+14$
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