$-28+\left(-1\right)+\left(-1\right)$
$\int6sec^3\left(x\right)dx$
$\left(5r+2t\right)^2$
$\left(3x^6-2x^4\right)$
$5x-2x+2=8$
$\int x^2\left(4x^3+4\right)^4dx$
$-5x+10\le-15$
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