$\frac{dy}{dx}=\frac{2x}{3y^2}y=2x^4+6x^3+x^2-5x-7$
$2x\:+8\:=\:x\:+\:15$
$\left(\frac{3}{2}x-y\right)^2$
$\lim_{x\to-4}\left(\frac{x-4}{x+4}\right)$
$\left(4x+7y+5z\right)^2$
$x^3\cdot y^{-5}$
$\sqrt[4]{16x^8}y^{12}$
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