$\left(6a+5b\right)\left(3a-7b\right)$
$-2x\ge-26$
$\frac{\sqrt{3}}{6}\arctan\left(\frac{\sqrt{3}}{2}\tan\left(x\right)\right)$
$\left(2x^3+6z\right)+\left(8y^3+3z\right)$
$9y^2+4z^2-x^2-18y-16z+4x+21=0$
$\left(5x-3\right)\left(x-3\right)$
$x^3-4x^2-11x+30$
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