$\left(2x+3\right)\cdot\left(3x-1\right)\cdot\left(4x\right)$
$3-\left(1\right)-\left(1\right)$
$2x^25x^2+5x-2$
$x+6\cdot x+3$
$\frac{1}{2}a^2-121$
$7\left(4-a\right)$
$+2020\:+\:-384$
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