# Step-by-step Solution

## Sort $mn^2x^2-3mn^3x-2+\frac{1}{8}x^3$ ascending with respect to $x$

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### Videos

$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$

## Step-by-step Solution

Problem to solve:

$order\left(m n^2 x^2-3m n^3\cdot x-2+\frac{1}{8} x^3,x,2\right)$
1

Apply the formula: $\mathrm{order}\left(x,a,b\right)$, where $a=x$, $b=2$ and $x=mn^2x^2-3mn^3x-2+\frac{1}{8}x^3$

$-2-3mn^3x+mn^2x^2+\frac{1}{8}x^3$
2

Factoring by $m$

$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$

$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$order\left(m n^2 x^2-3m n^3\cdot x-2+\frac{1}{8} x^3,x,2\right)$