$\left(3x^4+5\right)^2$
$-99x>99$
$\int x^3\left(x+6\right)^5dx$
$-4x^2+120x=0$
$-15\cdot2-\left(-1\right)\cdot5$
$6-2\cdot4+7$
$b^{-2}$
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