$- 3 x ^ { 2 } + 6 x + 1 = 0$
$\frac{x+3}{x}<7$
$-\int_1^2\left(cot^2\left(x\right)+1\right)\sec\left(x\right)dx$
$600\left(90-10\right)^2$
$2^{-\infty}$
$\lim_{x\to4}\sqrt[3]{x+4}$
$\frac{3x^2}{x^2+x}$
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