$8+7\cdot6-4$
$\frac{2x+6}{3x}=x-8$
$x+24<3x$
$\left(\sin\left(4b\right)+4\right)^2$
$x-5=11$
$\frac{\left(3x^4-18x^2-9x+6\right)}{x^2+3x+2}$
$r+3=3$
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