$2+\left(4+6\right)\left(2+4\right)$
$\lim_{x\to\infty}\left(6x+2\right)$
$x^2+9<3$
$3\left(2\right)^3+2\left(2\right)\left(-2\right)-4\left(-2\right)^2$
$14cos\left(x\right)=0$
$3x^2-x+4=-8x^2+6x+4$
$\int_0^x\left(t^{\frac{1}{2}}\right)dx$
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