$h\left(x\right)=e^{x+1}-1$
$\left(x-2\right)\left(x-3\right)<0$
$\left(3\cdot3\cdot3\right)\left(2\cdot2\cdot2\right)$
$24x^2-12$
$10ab^2-2ab+7b^2$
$b\left(b+a^2-1\right)$
$2^{12}\cdot2^{-6}$
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