$\tan\left(-x\right)=\tan x$
$3x^3+bx^2-5ax+7=cx^3-2x^2-10x+7$
$9.6-5.8$
$\left(\frac{3}{4}d+7\right)\left(\frac{3}{4}d-3\right)$
$16mn^2+48m+36$
$\frac{\left(4-x\right)^{.5\:}dy}{dx}=1-y$
$2cos^2x\:+\:\left(1+tan^2x\right)$
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