$\int\frac{1}{\left(x-1\right)^2\left(x^2+4\right)\left(x^2-1\right)}dx$
$d=nzx$
$1+-64$
$4n^2-20n+25$
$\frac{5}{2^x}+\frac{1}{3^x}$
$-\frac{1}{x+2}-3<0$
$\lim_{x\to\infty}\left(1+x^{-1}\right)^{x^2}$
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