$\left(x+5\right)\left(x+12\right)$
$16a^2b\:+\:12ab$
$\left(7k-4d\right)\left(4d+7k\right)$
$\int\left(\frac{\left(x^3-1\right)}{\left(x\left(x+1\right)^3\right)}\right)dx$
$\left(-1.0001\right)^2-5\left(-1.0001\right)$
$\frac{d}{dx}cos\:13x$
$a^6-12ab+36^2$
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