$3.\:\left(x\:+\:1\right)\:=\:2.\:\left(x\:+\:5\right)\:$
$x\frac{dy}{dx}-y=2x^2\csc\left(x\right)$
$\frac{-1}{v}=\frac{-v+5}{50}$
$x^2-8x-1008<0$
$\frac{x^3}{\left(3+x^2\right)^2}$
$x^{''}+4x^'+4x=0$
$\frac{d}{dy}y=x^2+x-3$
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