$\frac{6t-15}{3t-2}$
$2cos3x=1$
$2\left(-3\right)\left(-6\right)\left(5\right)$
$x^{\frac{1}{3}}+x^{-\frac{2}{3}}$
$8a-5b-8a+5b$
$\frac{3}{x+2}+\frac{6}{x^2+2x}=\frac{3-x}{x}$
$a\left(a+1\right)+b\left(b+1\right)$
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