$\left(-6x^2\right)\left(-9x^3\right)$
$2+\left(4+6\right)\left(2+4\right)+18$
$3.1+2.4+5.1+y+4$
$\frac{3}{\infty^3}$
$12\cdot\left(-3\right)+\left(-10\right)\cdot45$
$\frac{dy}{dx}=\frac{ysinx}{1+y^2},\:y\left(0\right)=2$
$\frac{-4b}{a^2}^3$
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