$x'\:+\:5x^2\:=\:25$
$\left(-3\right)\:+\:\left(-8\right)\:+\:\left(-4\right)\:-\:2\:x\:\left(-2\right)$
$y'-y=1+xe^x$
$-3x+5\left(x+4\right)<2\left(3x-2\right)$
$\sqrt[4]{a^8.b^{12}}$
$-20x^2+640x-4400$
$\lim_{x\to0}\left(\frac{sin\left(x^3\right)}{sin^3\left(x\right)}\right)$
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