$y\frac{dy}{dx}=6x^2y-\frac{3y^2}{x}$
$\int_1^{\infty}\left(\frac{1}{\sqrt{3x-1}}\right)dx$
$3x^2-10x+3$
$\left(3x^2-15\right)\left(3x^2+2\right)$
$\left(1+\sqrt[2]{-1}\right)^{20}$
$\int x\:sec^2\:6x\:dx$
$48\left|5\cdot3-2\cdot\left(6-10\right)-17\right|$
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