$\frac{x^0y^4}{\left(2x^{-3}y^3\right)^2}$
$\log\left(x+3\right)=\log7$
$\int_0^{\frac{\pi}{3}}\left(4secutanu\right)du$
$\:-6x+7=-47$
$a^3+cos^3x$
$\left(5y\right)^{-3}$
$\frac{x^2+3}{x\left(x^2+x+6\right)}$
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