$x-5=11$
$\lim_{x\to2}\left(\frac{\ln\left(x-2\right)}{\ln\left(x^2-4\right)}\right)$
$\left(x+3\right)^2=6x-16$
$1002\cdot998$
$\lim_{x\to0}\left(\cos\left(x\right)\right)^{\frac{4}{x^2}}$
$2x^5-4x^3+x-1$
$4cosx-1=2sinxtanx$
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