$\frac{d}{dx}cos\left(2x+3y\right)=x$
$\frac { - x ^ { 3 } } { 3 } | _ { - 1 } ^ { 1 }$
$\frac{dy}{dx}=\frac{1}{2}\cdot\left(\frac{x}{y}+\frac{y}{x}\right)$
$-384-64$
$x^2+8x-36=0$
$\int\:6xe^{3x}dx$
$x^2\:+\:27x\:-\:124$
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