$\left(x^2+x+1\right)\left(x^2+x+1\right)\left(x^4-x^2+1\right)$

$-2xy\:+\:\frac{2}{3}wyx;\:x=-2;\:y=\sqrt{3}\:z=3\:w=\frac{1}{2}$

$8\cdot\left|\left(-5\right)-\left(-9\right)+6-10\right|$

$\left(2x+12\right)^2=4x^2+24x+144$

$\lim_{x\to-1}\frac{1}{x}-\frac{1}{\left|x\right|}$

$2x\:-\:5\:<\:7x\:-\:3$

$\frac{\left(3x^2-5x+1\right)}{\left(x-4\right)}$