$2y'\:=\:7-3y$
$\sqrt[5]{\frac{x^2}{y^3}}$
$x^2+y^2=d^2$
$\int\frac{1}{x\sqrt[2]{7-x^2}}dx$
$x^2\left(a-1\right)-y^2\left(a-1\right)$
$6x^2+x-2=0$
$\left(x-11\right)\left(x-5\right)$
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